[spoiler][/spoiler]Guys, I put everything you need to know in my post.
I put the density of lead and tin in their grains per cubic centimeter, I provided the volume of the bullet in cubic centimeters and did the math for you.
I don’t think any of you read my post that showed that the bullet in question is a 50-50 mix of lead and tin by volume.
There is the small possibility, that because of the shape of the lead atom that the tin atom might be able to hide within the matrix to some degree, resulting in a decrease in volume with a mixture of the alloy, But I don’t think so.
I did read it, but it seemed so improbable that what little math skill I have was stuck in an endless loop of what-the-h..... And yes I do appreciate your contribution. Mike Rowe wrote here last year that these 1880s-1890s bullets were usually 12:1 alloy. I am chasing down the mass spec machine, because it seems the only way to really resolve this question.
