Originally Posted By: fnb25
YES! thanks heavens somebody gets it. if something is accelerated 20% faster it will generate 20% more force. if the terminal velocity is the same as whatever you're comparing it to, the kinetic energy will be the same and even the momentum will be the same. but the FORCE will be 20% greater. how fast it occurs hasn't got a bloody thing to do with whether or not someone can feel it.

forget physics 101. 3rd grade math will do. all anybody has to be able to do is multiply 2 numbers together and tell that the result is a larger number than the comparison.


How do you assume different accelerations? Different peak pressures aren't an assurance of that.

The discussion is predicated on identical kinetic energies...same mass, same terminal (muzzle) velocity, say 1200 fps. For one mass to accelerate 20% faster than the other, yet exit at the same 1200 fps suggests one load either 1)reaches 1200 fps somewhat sooner in the barrel, then remains essentially constant until exit or 2) the two loads reach different max velocities (>1200 fps) at different points within the barrel then slow down to exit coincidentally at the same 1200 fps. That's an interesting concept that actually could explain one recoiling "harder" than the other....if the two 1 ounce loads accelerated to different velocities within the barrel.

But.....that being the case, a simple ballistic pendulum that responded to the peak momentum and not necessarily the muzzle velocity would demonstrate that, i.e., 2 loads with same measured muzzle velocity would move the gun by different amounts, thus having demonstrably different free recoil energies.